4^x+2=(1/8)^x-5 tentukan nilai x
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[tex]{(4)}^{x + 2} = {(\frac{1}{8})}^{x - 5} [/tex]
[tex]{({2}^{2})}^{x + 2} = {(\frac{1}{{2}^{3}})}^{x - 5} [/tex]
[tex]{({2}^{2})}^{x + 2} = {({2}^{ - 3})}^{x - 5}[/tex]
[tex]{(2)}^{(2)(x + 2)} = {(2)}^{( - 3)(x - 5)} [/tex]
[tex]{(2)}^{2x + 4} = {(2)}^{ - 3x + 15} [/tex]
[tex]2x + 4 = - 3x + 15[/tex]
[tex]2x - ( - 3x) = 15 - 4[/tex]
[tex]5x = 11[/tex]
[tex]x = \frac{11}{5} [/tex]
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